(12/a^2)=1-(1/a)

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Solution for (12/a^2)=1-(1/a) equation:


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

12/(a^2) = 1-(1/a) // - 1-(1/a)

1/a+12/(a^2)-1 = 0

a^-1+12*a^-2-1 = 0

t_1 = a^-1

12*t_1^2+1*t_1^1-1 = 0

12*t_1^2+t_1-1 = 0

DELTA = 1^2-(-1*4*12)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-1)/(2*12) or t_1 = (-49^(1/2)-1)/(2*12)

t_1 = 1/4 or t_1 = -1/3

t_1 = -1/3

a^-1+1/3 = 0

1*a^-1 = -1/3 // : 1

a^-1 = -1/3

-1 < 0

1/(a^1) = -1/3 // * a^1

1 = -1/3*a^1 // : -1/3

-3 = a^1

a = -3

t_1 = 1/4

a^-1-1/4 = 0

1*a^-1 = 1/4 // : 1

a^-1 = 1/4

-1 < 0

1/(a^1) = 1/4 // * a^1

1 = 1/4*a^1 // : 1/4

4 = a^1

a = 4

a in { -3, 4 }

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